How to find day of the week from any date of the calendar?Magical way to wonder everyone.

Sohel Sahoo: Hello Everyone,

Now, we will study a technique of finding the day on which any date falls in any year of our commonly used calendar(Gregorian Calendar). By the help of this you can do magic& surprise anyone by saying their birthdays with the date only.

 After studying this technique, you will be able to predict the day on which any date falls  in less than 10- 15 seconds.

In any date there are 3 parts such as :  day,month&year(DD/MM/YYYY).Moreover, the year is more specifically consist of a century part (i.e. First 2 digits) and a normal year part (i.e. Last 2 digits).

e.g. 1974 = [Here 19 is the century part representing 1900& 74 is the normal years after the century part]

Types of Years in Calendar:-

Leap Year:-

(i). Every year which is divisible by 4 is a leap year, if it is not a century[ends in two zeros(00)]

(ii). Every 4th century means the year which is divisible by 400 is a leap year and no other century is a leap year.

Note:- A leap year has 366 days.

Examples:-

(i) Each of the years 1948, 2004, 1676 etc. is a leap year.Since, these are completely divisible by 4.

(ii) Each of the years 400, 800, 1200, 1600, 2000 etc. is a leap year as these are completely divisible by 400. 

(iii) None of the years 2001, 2002, 2003, 2005, 1800, 2100 is a leap year for not divisible by 4&400 respectively.

Ordinary Year/Normal Year:-

The year which is not a leap year is called an ordinary year or normal year. An ordinary year has 365 days.

Before proceeding with the technique, I will give you 3 sets of keys(codes) of the days,months&years. This keys(codes) will remain the same for any given date in our calendars.

 The day Codes:-

In this method of calculation, the final answer is obtained in the form of a remainder. On the basis of this remainder we are able to predict the day of the week. The remainder of final result is one of these day codes. 

The day keys are very simple and needs no learning. As our week starts with Sunday and ends in Saturday. So, the codes are starting from Sunday & ends in Saturday.

                  

Remainder	Day
1	Sunday
2	Monday
3	Tuesday
4	Wednesday
5	Thursday
6	Friday
0	Saturday

The Month Codes:-

Before proceeding with the technique, I will give you a key of the months. This key will remain the same for any given year asked in any date.

Note:-1. Make pairs of 3 months of the year & you will easily be able to memorize & utilize the codes anywhere feels necessary. Clearly ,you have 4 set of codes which can be remembered within fraction of seconds.

2. You will have to memorize these months’ keys. To help you to memorize the codes easily, here is a small poem to remember it for a long time:-

                                                                    It’s the square of twelve

                                                                     and the square of five

                                                                      and the square of six

                                                                    and one-four-six.

Since, we have taken pairs of 3digits;So,the squares of 5&6 should be written in 3 digits&this can be done by adding one 0 before the two.

(Note: The square of 12 is 144, the square of 5 is 025, the square of 6 is 036 and then you have 146.)

In tabular form the month codes can be expressed as below:-

Month	Code
January	1
February	4
March	4
April	0
May	2
June	5
July	0
August	3
September	6
October	1
November	4
December	6

The poem will help you to memorize the key codes easily. I request you to be familiar with this codes before proceeding ahead.

The century year codes:-

Note that after 400 years the codes start repetiting.So, by knowing the codes we can obtain the next century cycle by following the cyclic order.

Century Year	1600	1700	1800	1900
Code	6	4	2	0

Remember the next centuries 2000,2100,2200&2300 and also the previous centuries 1200,1300,1400&1500 will have century codes 6,4,2&0 respectively.

Each leap year century(i.e. divisible by 400) will have 6 as code & then code decreases by 2 as century proceeds forward&backward.

Procedures to find the day from a date:-

Next, we will do an overview of the steps used in predicting the day.

STEPS:-

1.       Take the day of the given date as it is.

2.       Add the month-key(code) of the given date .

3.       Add the century year-key i.e. according to first 2 digits of the year. (Example: if 1946 is given then century is 1900)

4.       Take the last two digits of the year (If the year is 1942 then take 42) & add it.

5.        Add the number of leap years from the century year. This can be obtain by dividing the last two digits of the year by 4& taking the quotient only.

             6.        Finally, add these values and divide the total by 7. Take the remainder and verify it with the day-key codes.

These are the six steps that are required to predict the day from any date given.

NOTE:-  If the given date falls on January or February month of a leap year then subtract 1 from the final remainder and the corresponding day will be the required answer.

(Q) What day is 1 March 1941?

Ans:-  The day can be found out by following the steps as done below.

·The day of the date is 1.

·Month key for march is 4.

·Century key for 1900 is 0.

·Last 2 digits of the given year is 41.

·No. of leap year is the quotient on dividing 41 by 4. Thus, we got it as 10.

·The total will be 1+4+0+41+10=56. Now by dividing 56 by 7 we have the remainder as 0.

So, our required day will be Saturday as checked by day codes table.

(Q) What is the day on 15th August 1947?

Ans:-  The day can be found out by following the steps :

·The day of the date is 15.

·Month key for August is 3.

·Century key for 1900 is 0.

·Last 2 digits of the given year is 47.

·No. of leap year is the quotient on dividing 47 by 4. Thus, we got it as 11.

·The total will be 15+3+0+47+11=76. Now by dividing 76 by 7 we have the remainder as 6.

So, our required day will be Friday as checked by day codes table.

  To calculate quite fast you can eliminate all 7 or no.s that adding up to  make 7or multiple of 7 as per remainder theorem.

Since I was explaining the concept for the first time to you, I solved the questions  in detail. However, as me moved to exam we solved them much faster. With enough practice you will be able to predict the day on which a date falls in less than 10 seconds. Once the century code,month key and the day keys are properly memorized then the remaining calculation is just elementary mathematics.You can do it in a child’s play.

(Q)Find the date on 10 February 1948?

Ans:-  The day can be found out by following the steps :

·The day of the date is 10.

·Month key for February is 4.

·Century key for 1900 is 0.

·Last 2 digits of the given year is 48.

·No. of leap year is the quotient on dividing 48 by 4. Thus, we got it as 12.

·The total will be 10+4+0+48+12=74.Since, here the given date is of February month in 1948 which is leap year we have to subtract 1 also. Now by dividing 73 by 7 we have the remainder as 3.

So, our required day will be Tuesday as checked by day codes table.

I suggest you to try a few dates to test whether you have understood the concepts or not. You can take any date and verify it with the calendar application of phone at the end of finding result.

(Q) Find day of the date 23 october 2013?

Ans:-  The day can be found out by following the steps :

·The day of the date is 23.

·Month key for October is 1.

·Century key for 2000 is 6. [2000 is a leap year & falls in category with 1600]

·Last 2 digits of the given year is 13.

·No. of leap year is the quotient on dividing 13 by 4. Thus, we got it as 3.

·The total will be 23+1+6+13+3=46. Now by dividing 46 by 7 we have the remainder as 4.

So, our required day will be Wednesday as checked by day codes table.

Hope, you enjoyed a lot by knowing this magical trick.With the help of this you can surprise people by telling their birthdays only by date & it would certainly help you in competitive exams.In the next article I am going to teach you the reason behind this formula'odd days' concept.Till then practise this technique to do magic even more quickly.

N.B:- All the tables used in this article and the verse of the rhyme written above are taken from Vedic mathematics made easy book written by Mr. Dhaval Bhatia Sir. He is a vedic maths TRAINER as well as memory TRAINER 🙏. Please consider buying the book from Amazon to learn amazing concepts regarding fasten up simplification and calculation in hands down.

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